Linked Question
There are 600 students in a school. The number of girls was at least 40% of the total students but did not exceed the number of boys. Every student chose at least one of two sports: swimming or running. 45% of the boys and 85% of the girls opted for swimming, while 75% of the boys and 55% of the girls opted for running. What are the minimum and maximum possible numbers of students who took part in both sports?
Think of this as: we know how many boys and girls picked each sport, and everyone picked at least one. The number doing both is fixed once we fix the number of girls — so the problem reduces to finding the allowed range for the number of girls, then checking the endpoints.
Step 1 — Set up variables and translate the constraints.
Let = number of girls, = number of boys. We know , so .
The problem gives two conditions on :
Girls are at least 40% of total:
Girls do not exceed boys:
So can range over the interval .
Step 2 — Express the number of students in each sport.
Step 3 — Use the inclusion–exclusion principle to find "both."
Since every student chose at least one sport, the union (at least one sport) equals the entire school = 600.
Step 4 — Substitute to get "both" in terms of alone.
💡 Teacher tip: The expression is linear in with a positive coefficient (). That means "both" increases as increases. So the minimum and maximum must occur at the two endpoints of 's range — no interior value can beat them.
Step 5 — Evaluate at the endpoints.
| Endpoint | Value | ||
|---|---|---|---|
| Minimum | |||
| Maximum |
Step 6 — Match with the options.
The minimum and maximum are 168 and 180, respectively, which corresponds to Option A.
Answer: 168 and 180 (Option A)
💡 Why this works so cleanly: Once "both" turned out to be a linear function of , the entire problem collapsed to checking two endpoints. Whenever a quantity is linear in a variable that ranges over an interval, the extremes always sit at the boundary — never in the middle.
The shortcut here: don't build a Venn diagram at all — just count total picks. Since every student picked at least one sport, the overlap is simply (total picks) − 600, because students in both sports got counted twice and everyone else once.
Step 1 — Range for the number of girls. Let be girls, so boys .
So .
Step 2 — Count picks per person. A boy contributes picks, a girl contributes picks. So:
Step 3 — Reduce to one variable. Substitute :
Therefore:
Step 4 — Read off the endpoints. This is linear and increasing in , so the extremes happen at the ends of 's range — no testing needed in between.
So the minimum and maximum possible numbers doing both sports are 168 and 180, which is Option A. Whenever an expression like this turns out linear in a variable with a bounded range, checking just the two endpoints is all you need — that's the takeaway for similar problems.
Final answer: A
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